题解归档 - cf535A

题解归档 - cf535A

本文由 cf-code 本地题解库自动归档;公开内容以本地 AC/验证版本为准。

思路

cf535A Tavas and Nafas

题意

把 0–99 的整数输出成英文小写单词;21–99 中非整十数用连字符,如 ninety-nine

做法

两张查表:a[0..19] 覆盖 zero 到 nineteen;b[2..9] 存整十词。若 s<20 直接输出 a[s],否则输出 b[s/10],个位非零再拼 "-"+a[s%10]

验证

样例 6/20/99 + 边界 0/21,WSL 编译运行通过(Kali 暂不可达)。

代码

来源:problems/cf535A/solution.cpp

/* Author: likely
 * Time: 2026-06-08 04:19:06
**/
#include<bits/stdc++.h>
#define ll long long
using namespace std;
string a[20]={"zero","one","two","three","four","five","six","seven","eight","nine","ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen"};
string b[10]={"","","twenty","thirty","forty","fifty","sixty","seventy","eighty","ninety"};
string ans;
int main(){
    ll s;
    cin>>s;
    if(s<20) ans=a[s];
    else{
        ans=b[s/10];
        if(s%10) ans=ans+"-"+a[s%10];
    }
    cout<<ans<<endl;
    return 0;
}
~  ~  The   End  ~  ~


 赏 
感谢您的支持,我会继续努力哒!
支付宝收款码
tips
文章二维码 分类标签:归档TypechoAutoUpload
文章标题:题解归档 - cf535A
文章链接:https://www.fangshaonian.cn/archives/356/
最后编辑:2026 年 6 月 28 日 19:07 By 方少年
许可协议: 署名-非商业性使用-相同方式共享 4.0 国际 (CC BY-NC-SA 4.0)
(*) 3 + 8 =
快来做第一个评论的人吧~