题解归档 - cf535A
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题解归档 - cf535A
本文由 cf-code 本地题解库自动归档;公开内容以本地 AC/验证版本为准。
- 本地编号:
cf535A - 本地来源:
problems/cf535A/idea.md - 题目链接:https://codeforces.com/contest/535/problem/A
- 原始标题:cf535A Tavas and Nafas
思路
cf535A Tavas and Nafas
题意
把 0–99 的整数输出成英文小写单词;21–99 中非整十数用连字符,如 ninety-nine。
做法
两张查表:a[0..19] 覆盖 zero 到 nineteen;b[2..9] 存整十词。若 s<20 直接输出 a[s],否则输出 b[s/10],个位非零再拼 "-"+a[s%10]。
验证
样例 6/20/99 + 边界 0/21,WSL 编译运行通过(Kali 暂不可达)。
代码
来源:problems/cf535A/solution.cpp
/* Author: likely
* Time: 2026-06-08 04:19:06
**/
#include<bits/stdc++.h>
#define ll long long
using namespace std;
string a[20]={"zero","one","two","three","four","five","six","seven","eight","nine","ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen"};
string b[10]={"","","twenty","thirty","forty","fifty","sixty","seventy","eighty","ninety"};
string ans;
int main(){
ll s;
cin>>s;
if(s<20) ans=a[s];
else{
ans=b[s/10];
if(s%10) ans=ans+"-"+a[s%10];
}
cout<<ans<<endl;
return 0;
}
~ ~ The End ~ ~
文章标题:题解归档 - cf535A
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最后编辑:2026 年 6 月 28 日 19:07 By 方少年
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